Sprintex or Vortech, which setup has more potential?

[Foobar]

Originally Posted by Adeets

I don't think over spinning is the proper term, over pressurizing would be better.

Yeah I wasn't sure - I was tempted to use "overboost" but went with "overspin".

[448hpsti]

Originally Posted by regal

Do you find your Vortech "lacking" in mid-range torque needing the wastegating? The complaint with centr. chargers has always been that for the money you don't gain much in a bigger powerband, mainly just up top (in comparison to a pos disp or turbo.)

The wg allows for smaller pulley yes, that equals lots more oomph at mid power band, why else do you think I'm playing with it?

[King Tut]

Originally Posted by Adeets

By that I mean wastegating at 9psi which means it can run 93, 5.4psi at 2500, 9 psi around 4200rpm

When can I see a 3rd gear boost plot that shows 5.4 psi at 2500 RPM?

[Adeets]

Originally Posted by King Tut

When can I see a 3rd gear boost plot that shows 5.4 psi at 2500 RPM?

Math, 16psi @7400.... (16/7400)2500 = 5.4 (full boost/max rpm)desired rpm = psi@desired rpm if psi>wastegate psi then psi@desired rpm = wastegate psi.

[whataboutbob]

Originally Posted by Adeets

I think most people who think of the innovate sound heard it thru @robispec and his videos, but with the ton of light weighting he's done I don't think the growl would be nearly as loud in a normal car.

Here you go. With an Invidia N1 and Invidia high flow catted front pipe too. All of the car's interior parts are still in place/OEM.

[ame]http://youtu.be/dSDWsX22daE[/ame]

[King Tut]

Originally Posted by Adeets

Math, 16psi @7400.... (16/7400)2500 = 5.4 (full boost/max rpm)desired rpm = psi@desired rpm if psi>wastegate psi then psi@desired rpm = wastegate psi.

Nice maths. I would still like to see a boost curve plot please.

[pheoxs]

Originally Posted by Adeets

Math, 16psi @7400.... (16/7400)2500 = 5.4 (full boost/max rpm)desired rpm = psi@desired rpm if psi>wastegate psi then psi@desired rpm = wastegate psi.

It's hard to do it like that because with the stock pulley I see 1psi around like 3k. Boost doesn't start from 0

Sent from my Nexus 4 using Tapatalk 4

[fenton]

Originally Posted by Adeets

Math, 16psi @7400.... (16/7400)2500 = 5.4 (full boost/max rpm)desired rpm = psi@desired rpm if psi>wastegate psi then psi@desired rpm = wastegate psi.

Only thing that makes that boost down low is the Electric supercharger. Doesn't make nearly as much up top though, for obvious reasons.

Bob at drift office tuned one with full boost starting at 1800rpm

Does anyone know if running a larger pulley on vortech increase parasitic power loss across the rev band? Like does it actually take more HP to turn the supercharger, or is it just the step to installing the actual charger that introduces the loss?

Anyways boost down that low is fun but you don't really use it that much.

My current setup makes 180tq at 2000 rpm with 4.5psi.

[Adeets]

Originally Posted by pheoxs

It's hard to do it like that because with the stock pulley I see 1psi around like 3k. Boost doesn't start from 0

Sent from my Nexus 4 using Tapatalk 4

Every boost graph I've seen of any centri is pretty much a completely flat line, from 0 to its red line, it's not a turbo or PD it's not gonna have a dynamic shift in pressure. 0 is 0, red line is max psi, everything in-between is a not a straight line, but is an ever so slight concave to it....

So 3psi at 2.5k

[fenton]

Its not really a straight line there are loses at the low end that aren't made up until the top end.

This is mostly due to the impeller design if I'm not mistaken ... I am not a expert though



Sent from my HTC One using Tapatalk 4

[Adeets]

Originally Posted by fenton

Its not really a straight line there are loses at the low end that aren't made up until the top end.

This is mostly due to the impeller design if I'm not mistaken ... I am not a expert though



Sent from my HTC One using Tapatalk 4

Already note in the post, read the last 2 sentances.

[Robftss]

Originally Posted by Adeets

Math, 16psi @7400.... (16/7400)2500 = 5.4 (full boost/max rpm)desired rpm = psi@desired rpm if psi>wastegate psi then psi@desired rpm = wastegate psi.

7400/2500= 2.96:1 ~1/3

So its the 3rd root of 16psi = 2.52 psi @ 2500 rpm.

Pressure is square of impeller rpm. (ideal).

[Adeets]

Originally Posted by Robftss

7400/2500= 2.96:1 ~1/3

So its the 3rd root of 16psi = 2.52 psi @ 2500 rpm.

Pressure is square of impeller rpm. (ideal).

Though your conculsion seems correct wouldn't that mean the blower has an exponential gain? Kinda like would u rather have a million dollars up front or a penny a day and double the sum everyday for 2 months?

[448hpsti]

Originally Posted by Robftss

7400/2500= 2.96:1 ~1/3

So its the 3rd root of 16psi = 2.52 psi @ 2500 rpm.

Pressure is square of impeller rpm. (ideal).

spot on sounding to me