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#113 | |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
Location: Seattle, WA
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Quote:
Your "point" doesn't hold any water because it DOES NOT make a single difference. It's people like you who try to come here and make a "point" just for the sake of making a point. What is it you're really arguing? "clear cut obvious"- uhh no, it's clear cut obvious that your point sucks. Lol get used to it when you have that kind of mindset. Refer to Razic's very eloquently stated and explained post about how you're so god damn wrong it hurts that you're still here >> http://www.ft86club.com/forums/showp...6&postcount=93Try again |
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| The Following User Says Thank You to Koa For This Useful Post: | cdrazic93 (02-18-2015) |
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#114 |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
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P.S. .... @CBR600RR ... nice taste in bikes at least. If I didn't pick up my '05 r6 for $2,000 with no fairings and a broken right clipon, I woulda went honda.
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#115 | |
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Banned
Join Date: Sep 2013
Drives: 2013 GBS BRZ Limited
Location: Colorado
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Quote:
Using those two numbers (drum angular velocity) and elapsed time (∆t), you can derive the power. Power is the rate of doing work. The work done is the change in rotational energy of the drum. If you start from a stop, w = 0 so rotational kinetic energy is zero The power is the final kinetic energy of the drum (in joules) divided by the time it took to spin the drum to the final speed. So rotational kinetic energy is E = 1/2*I*w^2 ( where E is in joules, I is drum rotational Inertia in kg-m^2, and w is angular velocity in radians/second). So total energy is: (Efinal - Estart)/time-to-reach-Efinal (in seconds). This will give an average "Joules per second" which is the definition of Watts. Note: this will only give you average power over the whole "pull" and will not provide the nice dyno charts we typically see which represent instantaneous power across the RPM range. This precisely how I calclulated an average hp draw of spinning just the driveshaft. for the driveshaft example: Rotational inertia of the 30 lb driveshaft (@3 inch diameter) is : 0.01974 kg.m^2 wstart = 0 RPM, wfinal = 5600 RPM 5600 RPM = 35185.8 radians per minute = 586 radians per second The energy stored in the driveshaft = E = 1/2 * .01974*586^2 = 3389 joules If it took 16.2 seconds to spin the driveshaft from zero to 5600 RPM, then the 3389 joules were spread out over 16.2 seconds so the power (energy per unit time) is: 3389 joules/16.2 seconds = 209.2 watts. 209 watts = .28 horsepower. Side note: So since the headlights consume more than 200 watts, I would argue that driving with your headlights off vs On, would make more of a difference than removing the entire 30 pounds from the driveshaft (NOT accounting for the reduction in overall vehicle weight). SO I am sure to start whole new flurry of naysayers with that one..... So to be clear which of the following experiments would make the bigger difference: Replace the stock driveshaft with a 15 pound lighter one (shed 15 pounds from vehicle weight AND 15 lbs from rotational mass at the driveshaft) and do a 1/4 mile run with the headlights ON AND Remove 15 pounds from the spare tire (shed 15 pounds of vehicle weight) and do a 1/4 mile run with the headlights OFF. Which run is faster? The one where you removed the weight from the spare tire, and drove with headlights off. |
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| The Following 2 Users Say Thank You to stugray For This Useful Post: | Captain Snooze (02-17-2015), Koa (02-17-2015) |
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#116 |
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Senior Member
Join Date: Mar 2013
Drives: R32 GTR, AW11 MR2 SC, GTS86 R
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I wonder why people get all defensive and hurt over being wrong, it's like the best thing ever since you won't make the same mistake again.
__________________
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#117 | |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
Location: Seattle, WA
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As Karl Seguin put it, "Learning is more important than Knowing" http://openmymind.net/2012/4/18/Lear...-Than-Knowing/ I follow that mantra with a zeal in all I do, both professionally as an accountant, passionately as a gearhead and musician, and personally as a lover and friend. It's all about knowing (pun intended) how to learn |
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| The Following 2 Users Say Thank You to Koa For This Useful Post: | stugray (02-17-2015), Tenament05 (02-17-2015) |
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#118 |
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Is not fast.
Join Date: Oct 2013
Drives: 2014 Whiteout M/T
Location: SoCal
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ITT: Lightweight driveshaft owners struggle to justify their $300+ purchases.
__________________
"America is all about speed. Hot, nasty, badass speed." - Eleanor Roosevelt, 1936
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#119 |
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Because compromise ®
Join Date: Jan 2012
Drives: Red Herring
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@stugray
Thank you for a detailed explanation.
__________________
My car is completely stock except for all the mods.
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#121 | |
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Add lightness!
Join Date: Apr 2012
Drives: 17' WRX
Location: Boston
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Quote:
Can you please tell me why you are absolutely fixated on 0-100mph acceleration test? Of all the tests to try and prove your opinion that is the best test (0-120mph would be better or better yet, a standing mile?) Who is talking about drag racing here except everyone that is trying to say driveshafts aren't a good mod for drag racing? Are we seriously still having this discussion? What you are doing is akin to determining the worth of an aerodynamic aid based on drag at 15mph. It just doesn't make sense. Sure your numbers aren't wrong but you are making the wrong comparison. Please tell me why you aren't seeking to disprove your own hypothesis before rattling off these inane examples? It's seriously annoying. You are myotically fixated on this singular example and that is horrible science. All these false choices you present are ridiculous too. Why can't someone remove the spare, turn off their headlights and have a lighter driveshaft? Do you go into every exhaust thread and tell people they are wasting their money, that mathematically, a turbo kit is the only way to go? $1000 for 5-10whp or $4000 for 100whp? Easy! Science! Drive on a cold day and make more power than that $300 intake. Science! One nerd to rule them all! Nanu nanu! |
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| The Following User Says Thank You to industrial For This Useful Post: | Koa (02-17-2015) |
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#122 | |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
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Quote:
All I read is, "mad mad mad mad mad mad"
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| The Following User Says Thank You to Koa For This Useful Post: | cdrazic93 (02-18-2015) |
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#124 | |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
Location: Seattle, WA
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Quote:
At the end of the day, the rotational weight savings does MINISCULE amounts of gain over the equivalent sprung amount... soooo much so, that realistically, no appreciable gain in lap time or performance to, in their opinion, warrant the $400 spent. Notice the bold is where the facts stop and opinion starts. How aligned one is to that opinion is open to debate. In my opinion, that $400 can be used for MUCH better purposes, if on a budget. If a dude(tte) really is looking to spent more money on his car, and already has a full header system/tune/brakes/whatever... fuck. go for it! but if he/she does and comes here to try and exclaim how amazing it is, and how they can definitely tell, etc... don't expect the people who understand the real forces at work to hold their tongue. |
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| The Following 3 Users Say Thank You to Koa For This Useful Post: |
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#125 | |
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Add lightness!
Join Date: Apr 2012
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Location: Boston
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To prove or disprove whether a driveshaft makes a tangible difference in responsiveness and ability to change directions at speed is an infinitely more difficult problem which hasn't been addressed by anyone mathematically. (because it's really hard without dedicated software) |
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#126 | |
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Banned
Join Date: Oct 2014
Drives: '02 RA Bugeye | '15 FRS
Location: Seattle, WA
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Quote:
We could discern real quick that such a miniscule variable wouldn't have a compounded, noticeable effect on the track. It's a no brainer once we combine Stu and Zardic's mathematical logic with the fact that DSS and other driveshaft companies fail to put any real world data out that backs up any claim for performance increases they may have. |
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| The Following User Says Thank You to Koa For This Useful Post: | cdrazic93 (02-18-2015) |
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