What should i do?

[zman]

I have 2 10" JL audio subwoofers with a 450watt Kenwood amp that i took off from my old scion tc. The problem i have it does not fit in the FRS trunk. Should i cut a inch of the box from the bottom or just buy a single 10" box from amazon and only use one speaker?

[grass138]

Since you already have two subs, might as well cut off the excess inch. Or, you can sell one of the subs which you can use to purchase the single 10 box. Good luck!

[Chimera]

You Could check out integrity concepts. They make corner load enclosures that should hold the 10s

[zman]

It's not going to affect sound quality or anything if i cut it?

[Integrity Concepts]

Originally Posted by zman

It's not going to affect sound quality or anything if i cut it?

Zman,
You should try to keep the internal volume of the enclosure within the manufacturers recommended range for best results. Making the enclosure too small could greatly affect the sound quality and the woofers long term performance. JL lists all of their woofers net enclosure specs on their website, add the sub displacement to the recommended volume and this is the gross volume each woofer chamber should have, measure the inside length, width, and height of your estimated cut size and multiply them then divide that number by 1728, stay within a close percentage of that number.

If you find that it works out and decide to proceed with a cut, peel the carpet back and see if you can pull off the lid or floor by prying in the seam. Make a clean level cut around the perimeter of the walls (not through the carpet, carpet should be peeled back) and then reglue (with wood glue) the piece back on and nail or screw it. Caulk the inside seam, clean up the sawdust from the inside of the carpet and reglue it down with spray glue, or recarpet the box all together. This is the best way to make a clean modification that will not have leaks.


Dan - Integrity Concepts

[mid_life_crisis]

Originally Posted by zman

I have 2 10" JL audio subwoofers with a 450watt Kenwood amp that i took off from my old scion tc. The problem i have it does not fit in the FRS trunk. Should i cut a inch of the box from the bottom or just buy a single 10" box from amazon and only use one speaker?

JL is usually pretty good about answering questions. In your situation I would ask them for the ideal size box for a pair of the speakers you have. It isn't always as simple as double the size of a box for one speaker. Make sure you include the exact model number.

[zman]

http://www.jlaudio.com/10w1v2-8-car-...-drivers-92073
This the speakers that i own. Is it okay if i buy a box that is larger then recommended? I think i just want to use one speaker and it says there that it supports jl audio speakers. Thanks

[Integrity Concepts]

Originally Posted by mid_life_crisis

JL is usually pretty good about answering questions. In your situation I would ask them for the ideal size box for a pair of the speakers you have. It isn't always as simple as double the size of a box for one speaker. Make sure you include the exact model number.

This is true, I guess I shouldn't assume the box is individually chambered.

Originally Posted by zman

http://www.jlaudio.com/10w1v2-8-car-...-drivers-92073
This the speakers that i own. Is it okay if i buy a box that is larger then recommended? I think i just want to use one speaker and it says there that it supports jl audio speakers. Thanks

That all depends, what is the internal volume of the enclosure that you are looking at? As a rule of thumb a larger sealed enclosure will typically allow the woofer to play lower tones but at the cost of power handling.

.

[zman]

The outside dimensions are 14.5x15x13.5 and its .75MDF

[Integrity Concepts]

Originally Posted by zman

The outside dimensions are 14.5x15x13.5 and its .75MDF

That enclosure is 1.22 cu ft and is almost twice as big as the amount recommended for 1 of your woofers. You should be looking for an enclosure half that depth for running only 1 of your 10's.

[zman]

How did you calculate that since it's not the interior dimensions? Last question i promise lol.

[Integrity Concepts]

Originally Posted by zman

How did you calculate that since it's not the interior dimensions? Last question i promise lol.

As long as there are no inset sides or end caps the interior width of the single chambered enclosure is the overall width minus the sides at .75" a piece, so 15-1.5 = 13.5". Then do the same with the other 2 dimensions and we end up with 13 x 13.5 x 12 which is 2,106 cu in divided by 1728 (1 sq ft in inches) and we get 1.21875 cu ft.