#### Answer

$\frac{-2}{3}\frac{y^{7}}{x^{5}}$

#### Work Step by Step

$\frac{-10x^2y^4}{15x^7y^{-3}}\\=\frac{-2}{3}x^{2-7}y^{4+3}\\=\frac{-2}{3}x^{-5}y^{7}\\=\frac{-2}{3}\frac{y^{7}}{x^{5}}$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$\frac{-2}{3}\frac{y^{7}}{x^{5}}$

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