Quote:
Originally Posted by old greg
Umm... Could you explain what exactly it is that you're trying to figure out? I think there's a bit of a language barrier as it were.
If you're asking what I think you're asking it's just trigonometry and it's included wheel rate. If your spring is 10deg from vertical, the effective spring rate at the lower attachment point would be k*cos(10deg). The same thing would apply to damper forces as well.
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I think this is what I'm asking.
I've been reading a bit and some of the frequency formulas deal with the following:
You start with 'coil rate', the basic spring. Then this is adjusted based on how it is mounted/difference from 90 degrees. Then this 'fitted rate' is adjusted based on leverage for the 'wheel rate'.
As for the damping forces, if the setup is a coil-over damper then doesn't the damper just 'see' the coil rate since it is in-line with the spring? Like you use the wheel rate for your frequency, but determine your damping based on the coil rate?