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Old 01-30-2013, 12:50 PM   #29
u/Josh
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Quote:
Originally Posted by Shankenstein View Post
f_nat1 = constant * sqrt(spring rate / sprung mass)
What is the purpose of the constant in the natural frequency calculations? I haven't seen that before.

Quote:
Originally Posted by Shankenstein View Post
Tire rate / spring rate < sprung mass / unsprung mass
Can you explain how you get to this conclusion from what you presented above? You can use mathematics/vibrations if you'd like.
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