Quote:
Originally Posted by Impureclient
So the tire moved at the top 11mm inwards? That seems like a lot. Did you use that link I put up and if so which figures did you use or did you figure it out on your own?
|
Yes. It does seem like a lot, but that's what the math says. Plus, remember that 10mm is 1cm. Really not a lot considering the hypotenuse is over 30cm and you are at the very top of the arc.
Now, there's a few assumptions made easier by your camber bolt choice. This assumes the center point of the outside of the wheel does not move laterally, which will cause the calculations to be off by whatever amount you move it using the bolt, assuming only one is eccentric. If both are eccentric it will even out.
I don't need a fancy calculator to do basic trigonometry. Here's the formula:
sin('camber')*('rollingRadius')='topLateralMovemen t'
sin(1deg)*(.632m/2)=.00551m=5.51mm
Edit, if you don't believe me, C is 316 (half of diameter) and X is 1 in that calculator you sent me. A is your answer, and if you subtract B from C you get the increase in vertical fender gap, though the gap increase is likely offset by the vertical motion caused by the spindle and wheel width moving the wheel center upwards relative to the fender.