[FRS Justin]

Originally Posted by totopo

On further retrospect... molarity is what is important, not weight, since it is a gas. Furthermore N20 disassociates in the cylinder (it requires high T), not the manifold.

So let's say you ran on 1 atm of pressure of PURE NOSS!!!!Z!!11! (/s). In effect, since each mole of N20 dissociates into half a mole of 02, that would equate to 50% atm partial pressure of 02.

So depending on your mixture of air vs N20 it would be somewhere between 20 and 50% effective 02.

edit (because math is fun!!!): 100% N2O would be 7.35 PSI of O2. To get that much with FI, given 20% of O2 in air you would need 2.5 atm worth of air, so an extra 1.5 atm of boost, which equals 22 PSI of boost!!!! just from the oxygen alone!

Very nice now lets talk about a wet shot of nitrous using E85 on a 4 cyl direct port system @55psi using jets 20 fuel and 41 N2o