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Old 06-09-2014, 09:57 AM   #29
DarkSunrise
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Quote:
Originally Posted by paulca View Post
Remember that torque does nothing unless it "operates over rotation".

Throwing units out of it for simplicity.

Power output = Torque * RPM.

So DarkSunrise your method needs to take account of the drop in RPM the torque is applied at. (As above if you just forget the units and multiply torque directly by RPM is easiest). If you actually want "Watts" or "Horsepower" there are a few more complexities.

Examples....

200Nm torque @ 3,000rpm == 100Nm torque @ 6,000rpm.
200Mn torque @ 6,000rpm > 220Nm torque @ 4,500rpm.

In terms of power output, which is the energy transferred to the car in the form of momentum. aka Speed.
In terms of calcuating power, that's correct. Power is greater when a given amount of torque is applied at a higher RPM.

Maybe I'm mis-understanding you, but I'm not trying to calculate power, I want to compare torque to the ground in two different gears at the same vehicle speed (i.e., shift point).

If 1st gear is putting down 2400 lbs-ft of torque at 7000 RPM, and 2nd gear would put down 1700 lbs-ft of torque at 4500 RPM, you would want to ride out 1st gear for as long as that torque value is above that in 2nd for the given vehicle speed.
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