[Dave-ROR]

Originally Posted by qoncept

It's still absolutely wrong. Play with the calculator below. You'll see that when you increase the maximum available force you also increase the maximum static (rolling) friction. In other words, if your brakes are stronger, you can apply more force before you lock them up. It's a chain that starts at the pad and ends at the road.

It's right here, clear as day. Unsubbed.

http://www.ajdesigner.com/phpfrictio...imum_force.php

Example:
We'll make up a coefficient for brake pads on rotors since I reall have no idea.. lets say 0.8.

- Stock brakes apply 20 newtons of force, which gives us a max of 16 newtons of friction on the rotor. Tires on road is a coefficient of .9, and the 16 newtons we're applying gives us stopping force of 14.4 newtons.

- Megabrake applies 25 newtons of force. Same coefficient of .8 means the rotor sees 20 newtons of friction, and then the tire on the road sees 18 newtons of maximum static friction.

Of course, the friction required to stop a car increases exponentially. Same deal with power and acceleration.

Since when does the amount of braking force determine the limits of adhesion for a tire? If you can EXCEED the limits of adhesion than a stronger brake setup nets you ABOLUTELY NOTHING except being able to exceed the limits of adhesion more easily and being able to exceed the limits of adhesion if you increase that limit (ie better tires). However, that will have no effect if the original brakes could also exceed the limits of adhesion that you just increased.

The tires stop the car. Period. If you can lock them up then threshold braking will net you the shortest stopping distance with any brake force >= the force required to threshold brake. You could generate 1,000 newtons, your stopping distance will NOT change (at that increase it might be worse since it would be much harder to threshold brake in that setup most likely ).