Quote:
Originally Posted by qoncept
- Stock brakes apply 20 newtons of force, which gives us a max of 16 newtons of friction on the rotor. Tires on road is a coefficient of .9, and the 16 newtons we're applying gives us stopping force of 14.4 newtons.
- Megabrake applies 25 newtons of force. Same coefficient of .8 means the rotor sees 20 newtons of friction, and then the tire on the road sees 18 newtons of maximum static friction.
Of course, the friction required to stop a car increases exponentially. Same deal with power and acceleration.
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Yes obviously more brake force means more brake force, but if the wheel locks up at just 10 newtons of stopping force, it doesn't matter if you have you a 4.4 or 8 or a bazillion newtowns in reserve. Push the pedal harder, you aren't going to stop faster. You also can't lock up the wheels, and then lock them up even more.
The tire doesn't care if your rotor diameter is bigger and/or your piston piston area has increased or even how hard you push the pedal. The ideal amount of force is the force right before the tire begins to slip because as you have pointed out, static mu is more than slipping/kinematic mu. This ideal amount may be easy to achieve (in most cases) on a stock vehicle on stock tires. You just push the pedal really hard and you have more than enough force.
For what it's worth, I've seen many brake tests where bigger brakes with equal tires resulted in
longer stopping distances. In some cases due to brake bias...and the fronts getting locked up too easily.
Quote:
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In other words, if your brakes are stronger, you can apply more force before you lock them up
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No, you can just lock them up more easily. It's the same amount of force. The force that the tire starts sliding at is not going to increase because you have more force available.
I really don't understand what you're getting at. I understand kinematics quite well.
- andy