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Oil Pressure via CPC Input (Ecutek)
Hi,
I am trying to get the oil pressure logged in Ecutek via the CPC input with no luck. I am hoping someone here can point me in the right direction. . I had this sensor installed: https://www.bosch-motorsport-shop.co...-10-bar-140-de . It is grounded to the car chassis, powered via the ECU and pinned to the CPC Input. . In Ecutek the CP sensor input was overwritten to use the CPC input and 2D table updated for the conversion of voltage to Pressure. . The oil pressure sensor is working properly and the right voltage is sent to the ECU (confirmed via a multimeter, at the pin) Looking at the data logged in ECUTEK the reading is showing a flat 10 bar all the time. Looking at the raw input via the parameter CPS voltage, it oscillates between 4.98V and 5V Looking at the previous posts https://www.ft86club.com/forums/showthread.php?t=61573 and https://www.ft86club.com/forums/showthread.php?t=94751 It looks like the input is not working, hence always reading 5V. I have a 2019 Australian 86. Any idea what is missing in my setup for this to work? Thank you! |
I think not working would give 0 instead of 4.98-5v
Did you hook up the output of the sensor to the correct cpc input pin in the ecu? https://www.delicioustuning.com/site...ecutek_brz.jpg |
Quote:
From that thread https://www.ft86club.com/forums/showthread.php?t=94751 It says Without a connection to a sensor, the voltage is pulled up and logs ~5V (~940mmHg). |
yes for a open circuit will give 5v actually
could be the fact you have a restyling car i m not familiar with cpc input unfortunately, but for example the rear o2 input got weird in restyling cars and it doesnt work as in prerestyling as subaru changed the way it s grounded so to make it work you would connect the ground of a sensor into rear o2, both to the ground itself of the connector AND then bridge it into chassis ground otherwise doesn t work could be something similar with cpc input, if you connected chassis ground, the ecu could not see it and think the input is an open circuit and give u 5v |
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