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Do we have a tire weight thread?
Everyone knows light wheels are better than heavy... but what about light tires? Anyone know of a tire weight chart floating around the internet?
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Tirerack.com gives you tire weights....
All you really need to know is Continental makes some of the lightest tires in a given size... Michelin and Dunlop are usually close behind. |
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Tire weight is even more important with the weight on the outside. Yep tirerack lists the weights. Also Tiresize as well. Got stock size Hankook Ventus Evos 19lbs. https://tiresize.com/tires/Hankook/V...-215-45R17.htm Continental DW's are light Pirelli PZ4 in 18's are 20 lbs https://www.tirerack.com/tires/tires...Z4XL&tab=Sizes |
Tire weight affects rotational inertia a lot more than wheel weight. However, it's still only on the order of 1.5x non-rotating mass (i.e, save 4 lb on tire weight and acceleration is improved as if you saved 6 lb).
But other tire qualities might be more important to you.. Continental tires are very lightweight, but they are in general also poorly rated for steering responsiveness and cornering stability. https://www.tirerack.com/tires/tests...y.jsp?ttid=190 Conti DW: "What We'd Improve: More precise steering response and handling" I've only had one set of Conti tires. They were lightweight for sure. But the sidewalls were limp and fun-to-driveness went right out the window... |
Didn't know Tire Rack listed weights. I just checked the Nitto website and they list their weights(Tire Rack doesn't sell Nitto). So the next guy who's curious will know.
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Yes they were on my list too and just as important they are light 19lbs stock size. I went with the Hankooks because I was able to spend $400 for the set and get a combined 60+100+75= $235 in rebates purchasing through discountiredirect. So $165 for a set of tires aint bad:D |
A lot of manufacturers list tire weights on their site, which is nice.
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This. Sometimes even the faster things don't feel as fast or as good to drive. Also, if anyone has any leads on a constant of rotational moment of inertia of an actual car wheel and tire and not the theoretical stuff that google keeps bringing up, I'd love that info. I had heard weight savings in the wheel/tire package is like saving 150% before and I'd also heard it is like 1000% and I got bored so I plugged through it. Power required to get a non-rotating item to a certain linear velocity in a certain time is: P=E/t=0.5*m*(v^2)/t Where: E= Linear kinetic energy of the item m = mass of the item v = linear velocity of the item (equal to car's velocity) t = time spent accelerating Rotational kinetic energy of the rotating wheel tire = 0.5*k*m*(R^2)*(w^2) = 0.5*k*m*(v^2) since v=R*w w=rotational velocity (radians/sec) R=radius of wheel/tire m = mass of the item v = linear velocity of the item (equal to car's velocity) So, Power to get a wheel/tire assembly to a certain linear velocity in a certain time equals: P=linear kinetic energy/t + rotational kinetic energy/t = [0.5*m*(v^2)/t]+[0.5*k*m*(v^2)/t] m = mass of the wheel/tire v = linear velocity of the wheel (equal to car's velocity) t = time spent accelerating k = inertial constant of rotation for wheel/tire setup Notice how the first half of that is the same formula as for the power required to move a non-rotating object, such as a passenger in the cabin, or the exact same wheel in the trunk. The latter part is the contribution due to the wheel rotating. So, Total power required for wheel assembly = power required if wheel was sitting in the trunk + [0.5*k*m*(v^2)/t] We can choose a speed and estimated acceleration time for our cars, and a decent wheel/tire mass guestimate: v= 60mph = 27 meters/second t = 7 seconds (rough 0-60 estimate for an NA twin) m = 55 lbs = 25 kg P for non rotating = [0.5*35 kg*(27(m/s)^2)/7 sec] = 1822 watts = 2.44 horsepower is required to accelerate 25 kg to 60 mph in 7 seconds P for rotating wheel/tire = 1822 watts + [0.5*k*35 kg*(27(m/s)^2)/7 sec] = 1822 watts + 1822*k watts = 2.44 horsepower + 2.44*k horsepower Get your k for the wheel/tire setup and you've got your answer as to how much the rotational part adds. |
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