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Engine, Exhaust, Transmission Discuss the FR-S | 86 | BRZ engine, exhaust and drivetrain. |
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01-02-2012, 01:30 AM | #43 |
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cubing something is raising it to the third power. 3 would be the exponent you use. growing exponentially is what happens when you use exponents...unless that wink is inferring some sarcasm that im missing because i refuse to read the previous posts...i guess that last statement is whats wrong with forums
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01-02-2012, 03:07 AM | #44 |
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Uh, sorry, that is pretty incorrect. The wink was just, random.
Exponential relation means it's of the form a^x. Or functionally, f(x+y)=f(x)f(y). Am I seriously having to clarify this? -_- Example of exponential relation: The charge in a capacitor discharging into a resistor over time. Exponentially decaying. Example of cube relation: Power due to fluid resistance as a function of speed. Water pump in your engine falls into this category. Aerodynamic drag falls into this territory. Example of square relation: The force due to fluid resistance as a function of speed. Another would be force vs. distance a spring is stretched. Example of linear relation: Frictional force as a function of force against the surface. In your transmission, valves, bearings you lose to friction energy proportional to the force on the surfaces. Typical "force relations" are 1st or 2nd degree polynomial functions, and acceleration, momentum, blah blah are all defined as derivatives/integrals of motion so you typically do not see "exponential growth" in this context. |
01-02-2012, 08:55 AM | #45 |
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I'll edit my post if it will help...
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01-02-2012, 02:16 PM | #46 | |
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Quote:
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01-02-2012, 02:47 PM | #47 | |
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Quote:
the cube relation would look like x ^3 exponential growth appears as 3 ^x the variable that changes must be the exponent, that is what makes it exponential growth. |
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01-02-2012, 03:39 PM | #48 |
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01-02-2012, 04:12 PM | #49 |
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okay i get what you are saying and you did specify that you were knit picking. i was just pointing out that no matter where you put constants and variable, the relation between the input and out put is exponential.
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01-02-2012, 04:52 PM | #50 | |
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If we accept your "definition", then any "power relation" (including squaring) would be "exponential". But we use the word exponential to describe what I just said, not any class of function with derivative non-constant. |
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01-02-2012, 09:46 PM | #51 |
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frictional drag and inertial loss
amen!! I'm anxious to see that torque curve. |
01-02-2012, 10:48 PM | #52 |
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4 pages and no dyno sheets
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01-03-2012, 12:14 AM | #53 |
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When you guys say bigger brakes reduce Hp (dyno results) do you actually mean bigger rotors? If not, I don't understand how brakes affect anything other than adding a little weight. Obviously im still learning the basics.
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01-03-2012, 07:02 PM | #54 |
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Any dyno that measures torque as the car is accelerating sees an increase in rotational mass as a decrease in torque. There is no actual loss of torque, but the dyno will incorrectly show it as such.
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01-04-2012, 12:53 PM | #55 |
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I don't think you will see dyno till the months that it gets released to be honest.
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01-04-2012, 02:22 PM | #56 |
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So it's going to take more power for a 600hp motor to turn a drivetrain than a 300hp motor because the 600hp motor is going to rev faster? Conceded. I still don't think it's going to be anywhere near a fixed percentage that people swear by though. If you use the internet standard 15% for manual transmissions, it takes 90hp vs 45 to turn the same transmission, driveshaft, diff, axles, and wheels. I'll stick with my fixed number, even if it's a little inaccurate.
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