Quote:
Originally Posted by tCsonfrs
Yeah thats a lot of work for LED turn signals, hard pass.
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How about this?
New Resistor Value = Stock Resistor Value * Stock Bulb Watts / New Bulb Watts.
NewR = 0.02 * 21 / LED_watt
NewR = 0.42 / LED_watt
That's it. The only thing you need to know is the LED bulb's power consumption value (watts).
1) Get a 1-watt resistor of the value you need (0.42 / LED_watt). For example, for 3 watt LED bulb, you need 140 milliohm resistor. 4w->105mOhm. 5w->84mOhm.
2) Get the flasher module out.
3) Desolder the shunt resistor.
4) Solder the new resistor in.
5) Put the flasher module back in.